Five years ago a man was seven times as old as his son. Five years hence, the father will be 3 times as old as his son. Find their present ages.
Answers
Let Present age of father be x years.
and present age of Son be y years.
Five years Ago ,
Father's age = x-5
Son's age = y - 5
According to Question ,
x - 5 = 7 (y -5 )
or x -5 = 7y - 35
or x =7y - 35 + 5
or x =7y - 30 --------------------------------------(ist)
Five Years Hence ,
Father's age = x+5
Son's age = y+5
According to question ,
x+5 = 3(y+5)
x+5 = 3y + 15
or x = 3y +15 - 5
or x=3y +10 ....................................(2nd)
From ist and 2nd we get
7y - 30 =3y + 10
or 7y - 3y = 10 +30
or 4y = 40
or y = 10
hence Present age of Son = 10 years
Substitute y= 10 in equation ist , we get
x = 7*10 - 30
or x= 70 - 30
or x= 40
Therefore Present age of Father = 40 years
Hope this helps you!!
Thank You!!
Answer:
Step-by-step explanation:
Let seven years, age of Swati was x years and age of Varun was 5x² years
Present age of Swati = ( x + 7 ) years
Present age of Varun = ( 5x² + 7 ) years
Given, after 3 years swati's age will be 2 / 5 of Varun's age.
Age of Swati after 3 years = ( x + 7 + 3 ) years = ( x + 10 ) years
Age of Varun after 3 years = ( 5x² + 7 + 3 ) years = ( 5x² + 10 ) years
Given, age of Swati after 3 years = age of varun after 3 years
( x + 10 ) = 2 / 5 × ( 5x² + 10 )
( x + 10 ) = 2( x² + 2 )
x + 10 = 2x² + 4
2x² - x + 4 - 10 = 0
2x² - x - 6 = 0
2x² - 4x + 3x - 6 = 0
2x( x - 2 ) + 3( x - 2 ) = 0
x = 2 [ Age can't be negative ]
Therefore,
present age of Swati = ( 2 + 7 ) = 9 years
present age of Varun = 5(2)²+7=27 years
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