five years ago a man was seven times as old as his son. five years hence,the father will be three times as old as his son.find their present ages
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and age of father40year
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Answer:
Step-by-step explanation:
Let seven years, age of Swati was x years and age of Varun was 5x² years
Present age of Swati = ( x + 7 ) years
Present age of Varun = ( 5x² + 7 ) years
Given, after 3 years swati's age will be 2 / 5 of Varun's age.
Age of Swati after 3 years = ( x + 7 + 3 ) years = ( x + 10 ) years
Age of Varun after 3 years = ( 5x² + 7 + 3 ) years = ( 5x² + 10 ) years
Given, age of Swati after 3 years = age of varun after 3 years
( x + 10 ) = 2 / 5 × ( 5x² + 10 )
( x + 10 ) = 2( x² + 2 )
x + 10 = 2x² + 4
2x² - x + 4 - 10 = 0
2x² - x - 6 = 0
2x² - 4x + 3x - 6 = 0
2x( x - 2 ) + 3( x - 2 ) = 0
x = 2 [ Age can't be negative ]
Therefore,
present age of Swati = ( 2 + 7 ) = 9 years
present age of Varun = 5(2)²+7=27 years
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