Math, asked by namratamarkaraha, 6 months ago


Five years ago a man was seven times as old as his son. Five years hence, the father will be
Three times as old as his son. Find their present ages.
a Find his present age.​

Answers

Answered by priyarksynergy
0

present age of father=f

present age of son=s

Step-by-step explanation:

  • five years ago f-5=7*(s-5)
  • also f=3s
  • 3s-5=7s-35
  • 30=4s
  • s=7
  • f=21
  • present age of father is 21 and son is 7.
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