five years ago a man was seven times as old as his son. five years hence, the father will be three times as old as his son. find their present age
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son's Age is 10 years and father's Age is 40 years.
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Let y be the age of son.
Let 7y be the age of father.
y + 5 , 7y + 5 are the present ages
= y + 10 future age of son.
7y + 10 is father.
= (7y + 10 = 3) (y + 10)
= (y = 5)
= (7y = 35)
(y + 5 = 5 + 5 = 10)
.•. 10 years is age of son and
(7y + 5 = 7) ×( 5 + 5 = 40) .•. 40 is age of father.
Hope it helps!
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