Question

Five years ago a man was seven times as old as his son. Five years hence, the father will be
three times as old as his son. Find their present ages.​

Answer 1

SOLUTION :-

Five Years Ago,

• Age Of Son = x.
• Age Of Father = 7x.

Present Time,

• Age Of Son = x + 5.
• Age Of Father = 7x + 5.

After 5 Years,

• Age Of Son = x + 10.
• Age Of Father = 7x + 10.

According To The Question,

➙ 7x + 10 = 3(x + 10).

➙ 7x + 10 = 3x + 30.

➙ 7x – 3x = 30 – 10.

➙ 4x = 20.

➙ x = 20/4.

➙ x = 5.

Therefore,

• Present Age Of Son = x + 5 = 10 Years.
• Present Age Of Father = 7x + 5 = 40 Years.

Answer 2

ANSWER

Let Five years ago the age of son be x years and age of father be 7x years

Present age of son =x+5

Present age of father =7x+5

5 years later their age will (x+10) and (7x+10)

∴7x+10=3(x+10)

7x−3x=20

4x=20

x=5

So, the present age of son=x+5=5+5=10years

and the present age of father=7x+5=35+5=40years

⭐itZphantoM⭐