Math, asked by aroranalin1607, 4 months ago

Five years ago a man was seven times as old as his son. Five years hence, the man will be three
times as old as his son. Find their present ages.

Answers

Answered by Dev12432
2

Answer:

present age of father is 40 and son is 10

Step-by-step explanation:

Let Five years ago the age of son be x years and age of father be 7x years

Present age of son =x+5

Present age of father =7x+5

5 years later their age will (x+10) and (7x+10)

∴7x+10=3(x+10)

7x−3x=20

4x=20

x=5

So, the present age of son=x+5=5+5=10years

and the present age of father=7x+5=35+5=40years

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