Question

five years ago a man was seven times as old as his son.five years hence ,the father will be three times as old as his son. find their present age

Answer 1

Here is ur answer.......

Let the past age of son = x
Let the past age of father = 7x
So,
Present ages are x+5 and 7x+5
Future age of son = x+10
Future age of father = 7x+10
Given
7x+10 = 3*(x+10)
7x+10 = 3x+30
7x-3x = 30-10
4x = 20
x = 20/4
x = 5
7x = 35
x+5 = 10
7x+5 = 40

Hope it helps......
:-):-)