Five years ago a man was seven times as old as his son. Five years hence the father will b three times as old as his son. Find their present ages
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Age of the son =x
Age of the father=7x
Present ages=x+5 and 7x+5
future age of the son=x+10
father=7x+10
7x+10=3(x+10)
x=5
7x=35
x+5=5+5=10
son age =10
father age =7x+5=7*5+5=40
Age of the father=7x
Present ages=x+5 and 7x+5
future age of the son=x+10
father=7x+10
7x+10=3(x+10)
x=5
7x=35
x+5=5+5=10
son age =10
father age =7x+5=7*5+5=40
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