Math, asked by mathewvaidyan6302, 1 year ago

Five years ago a man was seven times as old as his son five years hence , the father will be three times as old as his son .Find this hoes ent ages. Give solution

Answers

Answered by prashantkumar47
0

let son age five years ago be x

then

man age be 7x

5years hence

son age = x+10

and father age= 7x+10

so

3(x+10)= 7x +10

3x+30= 7x+10

7x- 3x =30-10

4x= 20

x =5 is

and

son present age 10 years

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