Question

five years ago a man was thrice as old ashis sonand 10 years laterhe shall be twice as old as his son find present age. please guys answer immediately​

Answer 1

Answer:

40

Step-by-step explanation:

Age of the son =x

Age of the father=7x

Present ages=x+5 and 7x+5

future age of the son=x+10

father=7x+10

7x+10=3(x+10)

x=5

7x=35

x+5=5+5=10

son age =10

father age =7x+5=7*5+5=40

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Answer 2

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Let the

=> present ages of son = 'x'years

=> present age of man = 'y'years

A to Q:-

5 years ago,

Their ages were -

Son = (x - 5) years

Man = (y - 5) years

.According to 1st condition :-

(y - 5) = 3(x - 5)

y - 5 = 3x - 15

3x - y = 10

y = 3x - 10. ----(1)

10 yrs later,

Son = (x + 10) yrs

Man = ( y + 10) yrs

According to 2nd Condition :-

(y + 10) = 2(x + 10)

y + 10 = 2x + 20

y - 2x = 20 -10

y - 2x = 10. ----(2)

Put the value of (1) in (2), we get,

(3x - 10) - 2x = 10

3x - 10 -2x = 10

x = 10 +10 = 20

x = 20. ------(3)

Put (3) in (1),we get,

y - 2(20) = 10

y = 10 + 40 = 50

y = 50

Hence,

Son = x = 20 yrs

Man = y = 50 yrs