Question

five years ago.a mother age was four times that of her daughter.In four years to come,she will be 5/2 times the age of her daughter .Calculate the sum of their present ages

Answer 1

Let present ages of mother be m and daughter be d.

5 years ago,
m-5 = 4(d-5)
m-5 = 4d-20

4 years later
m+4 = 5/2(d+4)
m+4 = 5d/2 + 10

Solve the equations.