Question

five years ago A mother was 7 times as old as her daughter five years hence she will be 3 times as old as her daughter find their present ages

Answer 1

let the age of mother=x years

age of her daughter= y years

so, from question

           x-5=7(y-5)

           x-5=7y-35

          x-7y=-30      (equation 1)

  now,

          x+5=3(y+5)

          x+5=3y+15

          x-3y=10       (equation 2)

subtracting 1 and 2,

               -4y=-40

               y=10      (3)

             now, x-3y=10

                     x-30=10       (from 3)

                     x=40        

Hence mother is 40 years old and her daughter is 10 years old