Question

Five years ago, a mother was 7 times as old as her daughter. Give year hence, she will be three times as old as her daughter. Find their present ages.
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Answer 1

Answer:

Step-by-step explanation:

Answer 2

At present

Daughter's age = x years

Mother age =y

5 years ago

Daughter's age =x-5

Mother's age = y-5

Mother's age=7*daughter's age

y-5=7(x-5)

y-5=7x-35

7x-y=30----(1)

After 5 years

Mother's age =y+5

Daughter's age =x+5

Mother's age=3*Daughter's age

y+5=3(x+5)

y+5=3x+15

3x-y=-10----(2)

Subtract (2) from (1)

4x=40

x =40/4

x=10

Substitute x=10 in (2)

3*10-y= -10

30-y =-10

-y =-10-30

y =40

At present

Daughter's age =x =10 years

Mother's age =y=40years

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