five years ago,a mother was seven time as old as her daughter. Five years hence, she will be three times as old as her daughter . find their present ages
Answers
Assumption
Present age of the daughter be 'p'
Now,
Five years ago,
Daughter age = p - 5
= 7(p - 5)
= 7p - 35
Present Age
= p - 5 + 5
= p
Also,
= 7p - 35 + 5
= 7p - 30
Five years hence,
Daughter age = p + 5
= 7p - 30 + 5
= 7p - 25
Situation
After 5 years, mother will be 3(thrice) daughter's age.
7p - 25 = 3(p + 5)
7p - 25 = 3p + 15
7p - 3p = 15 + 25
4p = 40
p = 10
p = 10 years
= 7p - 30
= 7(10) - 30
= 70 - 30
= 40 years
Let the daughters age be x
Before 5 years:-
Mother's age = 7 (x-5)
Daughters age =x-5
At present age:-
Daughters age = x - 5 +5= x
Mother's age = 7x - 5 + 5=7x-30
Five years hence:-
Daughters age=x+5
Mother's age = 7x-30+5=7x-25
According to question:-
After 5 years mother will be thrice of daughter's age:-
7x-25=3(x+5)
7x-25=3x+15
7x-3x=15+25
4x=40
X=10
Answer:- so, daughters age =x=10years
Mother's age =7x-30=40 years
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