Math, asked by ritasharan632, 10 months ago

five years ago,a mother was seven time as old as her daughter. Five years hence, she will be three times as old as her daughter . find their present ages​

Answers

Answered by Anonymous
106

\Large{\textbf{\underline{\underline{According\:to\:the\:Question}}}}

Assumption

Present age of the daughter be 'p'

Now,

Five years ago,

Daughter age = p - 5

{\boxed{\sf\:{Mother\;Age}}}

= 7(p - 5)

= 7p - 35

Present Age

{\boxed{\sf\:{Daughter\;Age}}}

= p - 5 + 5

= p

Also,

{\boxed{\sf\:{Mother\;Age}}}

= 7p - 35 + 5

= 7p - 30

Five years hence,

Daughter age = p + 5

{\boxed{\sf\:{Mother\;Age}}}

= 7p - 30 + 5

= 7p - 25

Situation

After 5 years, mother will be 3(thrice) daughter's age.

7p - 25 = 3(p + 5)

7p - 25 = 3p + 15

7p - 3p = 15 + 25

4p = 40

\tt{\rightarrow p=\dfrac{40}{4}}

p = 10

\Large{\boxed{\sf\:{Present\;Age\;of\;Daughter}}}

p = 10 years

\Large{\boxed{\sf\:{Present\;Age\;of\;Mother}}}

= 7p - 30

= 7(10) - 30

= 70 - 30

= 40 years

Answered by munutripathy1
88

Let the daughters age be x

Before 5 years:-

Mother's age = 7 (x-5)

Daughters age =x-5

At present age:-

Daughters age = x - 5 +5= x

Mother's age = 7x - 5 + 5=7x-30

Five years hence:-

Daughters age=x+5

Mother's age = 7x-30+5=7x-25

According to question:-

After 5 years mother will be thrice of daughter's age:-

7x-25=3(x+5)

7x-25=3x+15

7x-3x=15+25

4x=40

X=10

Answer:- so, daughters age =x=10years

Mother's age =7x-30=40 years

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