Question

Five years ago, a mother was seven times as old as her daughter. five years hence, she will be three as old as her daughter. find their present ages.​

Answer 1

Answer:

Step-by-step explanation:

Let present age of mother be x years

Age of daughter be y years

x - 5 = 7 ( y - 5 )

x - 5 = 7y - 35

x - 7y = -30 (1)

x + 5 = 3 ( y + 5 )

x + 5 = 3y + 15

x - 3y = 10 (2)

Subtracting (1) from (2),

x - 7y = -30

x - 3y = 10

- + -

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-4y = -40

y = 10 years

Putting y = 10 in (2),

x - 3*10 = 10

x = 10 + 30 = 40

The age of mother & daughter is 40 years & 10years respectively

I hope this will help you..