Question

Five years ago, a mother was seven times as old as her daughter. Five years hence, she will be three times as old as her daughter. Find their age.​

Answer 1

Answer:

Mother's age= 40 years

Daughter's age =10 years

Step-by-step explanation:

Let the present age of the daughter be 'x'.

5 years ago,

Daughter's age = x - 5

Mother's age = 7(x - 5) = 7x - 35

At present,

Daughter's age = x - 5 + 5 = x

Mother's age = 7x - 35 + 5 = 7x - 30

5 years hence,

Daughter's age = x + 5

Mother's age = 7x - 30 + 5 = 7x - 25

But according to the question, after 5 years, mother will be thrice daughter's age.

7x - 25 = 3(x + 5)

7x - 25 = 3x + 15

7x - 3x = 15 + 25

4x = 40

x = 40/4

x = 10

Daughter's present age = x = 10 years.

Mother's present age = 7x - 30 = 7(10) - 30 = 70 - 30 = 40 years.