Question

five years ago,a mother was seven times as old as her daughter. five years hence,she will be three times as old as her daughter. find their present ages.​

Answer 1

Answer:

Similarly,5 years from now the mother's age will be y+5=3(x+5)

By solving both the equations we get x=10 & y=40.

So the present ages of mother and her daughter are 40 & 10 years respectively.

Step-by-step explanation:

Answer 2

So , Let the present age of the daughter be 'x'.As per question

5 years ago,

Daughter's age = x - 5

Mother's age = 7(x - 5) = 7x - 35

At present,

Daughter's age = x - 5 + 5 = x

Mother's age = 7x - 35 + 5 = 7x - 30

5 years hence,

Daughter's age = x + 5

Mother's age = 7x - 30 + 5 = 7x - 25

But according to the question, after 5 years, mother will be thrice daughter's age.

✓ 7x - 25 = 3(x + 5)

= 7x - 25 = 3x + 15

= 7x - 3x = 15 + 25

= 4x = 40

= x = 40/4

= x = 10

Daughter's present age = x = 10 years.

Mother's present age = 7x - 30 = 7(10) - 30 = 70 - 30 = 40 years.

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