Question

Five years ago, A's age was 5 years less than twice B's age. Three years from now, one third of B's age will be 12 years less than A's age. Find their present ages. Plzzzzzzzzz Answer My Question​

Answer 1

Step-by-step explanation:

A's Present age = y

B's present age=x

given , (five years ago)

y-5 = 2(x-5)-5

ie , y-2x=-10 ---------(1)

given , (after 3 years)

y +3 -12 = 1/3 (x + 3)

ie, 3y- x=30-------- (2)

(eq(2) * 2 ) - eq(1) gives

y = 14

subsititute y = 14 in eq (1) ,

we get x = 12 .

therefore A's age is 14 and B's age is 12

I hope it helps !!

Answer 2

Answer:

Let the present age of A be 'x ' years & B be y years.

x = y-10

x-y = -10

Four years hence A= (x +10) years

Four years hence B = ( y+ 10) years

x+10/y+10 = 3/5

5(x+10) = 3(y+10)

5x+50 = 3y + 30

5x-3y = 30–50

5x-3y = -20 ————(2)

Multiplying first equation by 3

3x-3y = -30 ————(3)

Subtraction (2) - (3)

2x= 10

x = 5

Substituting x= 5 in equation (1)

5= y-10

y= 15

Step-by-step explanation: