Question

Five years ago a's age was 5 years less than twice b's age.3 years from now one third of b's age will be 12 years less than a's age. find their present age

Answer 1

Hi.

Good Question and Keep Progressing.

Here is your answer---

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Let the age of the A and B  five years ago be x and y respectively.

According to the question,

      x  = 2y - 5      ---------------------------------------eq(i)

Now, present age of A = (x + 5) years.
         ---------------------- B = (y + 5)years.

After 3 years from present age of A = (x + 5)+ 3 years.
 -------------------------------------------------- =(x + 8) years.
------------------------------------------------B = (y +5) +3 years.
                                                             = (y + 8) years.

According to the question,

   1/3(y + 8) = (x +8) - 12
   y + 8 = 3( x + 8 -12)
    y + 8 = 3(x - 4))
    y + 8 = 3x - 12
     3x - y = 12 + 8
    3x - y = 20 --------------------------------------------------eq(2)

Putting eq(1) in eq(2),
       3(2y - 5) - y = 20
        6y - 15 - y = 20
          5y = 20 + 15
          5y = 35
           y = 7 years.

Putting y = 7 in eq(i)
We get,
       x = 2(7) - 5
       x = 14 - 5
       x = 9 years.

Thus, Present age of A = x + 5
                                        = 9 + 5
                                        = 14 years.
------------------------------ B = y + 5
                                        = 7 + 5
                                         = 12 years.

Hope it helps.

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Have a nice day.

Answer 2

maths kiya jata hai .kaise karthe hai ye nahi d