Math, asked by Siboon, 1 year ago

Five years ago A's age was four times of B. Five years hence, A's age was two times of B. Find their present ages.

Answers

Answered by Crystal1111111111111
1


Let assume that The present ages of them be x

Five years ago A age is 4 Times of b

So 5 ×4 20





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Answered by Simplebeing
3
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The present ages

A's age -10yrs

B's age - 25 yrs.

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