Question

Five years ago, A's age was four times the age of B. Five years hence, A's age will be twice the age of B. Find their present age. ​

Answer 1

Answer:

let the present age of B=x

so the present age of A=2x

five years ago,

age of B=x-5

age of A=2x-5=4x

so,

the present age of B=5/6

the present age of A=5/6×2=5/3