Question

Five years ago, A was thrice as old aa B and ten years later A shall be twice as old as B, then the present age of A​

Answer 1

Answer:

Let the age of A=x years And the age of B=y years

Five years ago,

A's age =(x−5) years B

′

s age =(y−5) years

According to the question, (x−5)=3(y−5)

⇒x−5=3y−15

⇒x=3y−10…(i)

Ten years later,

A's age =(x+10) B's age =(y+10)

According to the question,(x+10)=2(y+10)

⇒x+10=2y+20

⇒x=2y+10…( ii )

From Eq. (i) and (ii), we get 3y−10=2y+10

⇒3y−2y=10+10

⇒y=20

On putting the value of y=20 in Eq. (i), we get x=3(20)−10

⇒x=50

Hence, the age of person A is 50 years and Age of B is 20years.

Step-by-step explanation:

please verified my answer

Answer 2

Answer:

hence 20 is correct answer

Step-by-step explanation:

please verified my answer