Question

Five years ago A was thrice as old as B and 10 years later A shall be twice as old as B, what is the present age of A?​

Answer 1

Answer:

Let,

Age of A=x

Age of B=y

x-5=3(y-5)

⇒x-5=3y-15

⇒x=3y-10. (1)

x+10=2(y+10)

⇒x+10=2y+20

⇒3y-10+10=2y+20  (Substituting the value of x).

⇒3y-2y=20

⇒y=20.

x=3y-10

⇒3(20)-10

⇒50.

∴The age of A is 50.

Answer 2

Step-by-step explanation:

let present age of A be X

let present age of B be Y

FIVE YEARS AGO

Age of A is x-5

Age of B is y-5

given (from question)

x-5=3(y-5)

x-5=3y-15

X=3y-10 ----(1)

TEN YEARS LATER

AGE of A Is X+10

Age of B is Y +10

given (from question)

x+10=2(y+10)

X+10=2y+20

x=2y+10

substitute (1)

3y-10=2y+10

y=20

put y=20 in (1)

X=3(20)-10

X=50

So, Age of A is 50

Age of B is 20

hope it helps you