five years ago a was thrice as old as B and 10 years later a shall be twice as old as B then the present age of a
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Let the age 5 yrs ago
Age of b = x
Age of a= 3x
A. T. Q
3x+15=2(x+15)
3x+15=2x+30
3x-2x=30-15
1x=15
Age of b 5 yrs ago = 15
Present age of b = 10
Present age of a = 40
Age of b = x
Age of a= 3x
A. T. Q
3x+15=2(x+15)
3x+15=2x+30
3x-2x=30-15
1x=15
Age of b 5 yrs ago = 15
Present age of b = 10
Present age of a = 40
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0
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