Five years ago, A was thrice as old as B and ten years later, A shall be twice as old as B What is the present age of A ?
Answers
Given
Five years ago, A was thrice as old as B and ten years later, A shall be twice as old as B
To find
Find the present age of A
Solution
★ Let A's age be x and B's age be y
**According to the given condition**
- Five years ago
- A's age = x - 5
- B's age = y - 5
➨ (x - 5) = 3(y - 5)
➨ x - 5 = 3y - 15
➨ x - 3y = -15 + 5
➨ x - 3y = -10 ---(i)
- Ten years later
- A's age = x + 10
- B's age = y + 10
➨ (x + 10) = 2(y + 10)
➨ x + 10 = 2y + 20
➨ x - 2y = 20 - 10
➨ x - 2y = 10 ---(ii)
✑ Subtract both the equations
➨ (x - 3y) - (x - 2y) = -10 - 10
➨ x - 3y - x + 2y = -20
➨ - y = -20
➨ y = 20
✑ Putting the value of y in eqⁿ (i)
➨ x - 3y = -10
➨ x - 3*20 = -10
➨ x - 60 = -10
➨ x = 60 - 10
➨ x = 50
Hence,
Present age of A = x = 50 yrs
Present age of B = y = 20 yrs
GIVEN:
- Five years ago, A was thrice as old as B
- Ten years later, A shall be twice as old as B
TO FIND:
- What is the present age of A ?
SOLUTION:
✪ Case 1 ✪
☞ Five years ago, A was thrice as old as B
- A's age = (A-5)
- B's age = (B-5)
According to given conditions:-
✪ Case 2 ✪
☞ ten years later, A shall be twice as old as B
- A's age = (A + 10)
- B's age = (B + 10)
According to given conditions:-
Now, put the value of 'A' from equation 1) in equation 2)
Put the value of 'B' in equation 1)
❝ Hence, the present age of 'A' is 50 years and that of 'B' is 20 years ❞