Question

Five years ago, A was thrice as old as B and ten years later A shall be twice as old as B . what are the present ages of A and B?​

Answer 1

Step-by-step explanation:

Let the present age of B and A be x years and y years respectively.

And A's age 5 years ago

= (y-5) years. B's age 10 years hence

= (x+10)years. A's age 10 years hence

= (y+10) years.

Answer 2

Answer:

Given :

1. Five years ago a was three times as old as b

2. Ten years later a shall be twice older than b.

Assume that present age of a as x and that of b as y.

Five years ago, a was thrice as old as b

i.e. age of a was x - 5 and age of b was 3(y-5)

x - 5 = 3 (y - 5)

x - 5 = 3y - 15

x - 3y = -15+5

x - 3y = -10 ---------(1)

Ten years later, a shall be twice as old as b

i.e. age of a will be x + 10 and age of b will be 2(y+10)

x + 10 = 2 (y + 10)

x + 10 = 2y + 20

x - 2y = 20-10

x - 2y = 10 ---------(2)

By elimination method, we get

x - 3y = -10

x - 2y = 10

- y = -20

y = 20 i.e. present age of b

Substituting y = 20 in equation 1, we get

x - 3y = -10

x - 3(20) = -10

x - 60 = -10

x = -10 + 60

x = 50 i.e. present age of a.

Step-by-step explanation:

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