Question

Five years ago, A was thrice as old as B and ten years later, A shall be twice as old as B. What are the present age of A and B?

Answer 1

Answer:

Let the present age of B and A be x years and y years respectively. And A's age 5 years ago = (y-5) years. B's age 10 years hence = (x+10)years.

5 years ago A is thrice as old as B

(A-5)=3(B-5)

A-5=3B-15

A=3B-10…..(1)

Ten later,A shell be twice as old as B ,So

(A+10)=2(B+10)

A+10=2B+20

A-2B=10

Substituting A value from eq(1)

(3B-10)-2B=10

3B-2B=10+10

B=20

From eq(1)

A-2(20)=10

A-40=10

A=50

Therefore our values are

A=50

B=20

A+B=50+20=70

Explanation:

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Answer 2

Answer:

present age of "a" is 50 years & "b" is 20 year