Math, asked by aanshii83, 8 days ago

five years ago A was thrice as old as B and ten years later. A shall be twice as old as B. what is the present age of A​

Answers

Answered by rathoreanushka34
1

Answer:

Correct option is

D

50,20

Let the age of A be a, and age of B be b

Now, a−5=3(b−5)

a=3b−10 (1)

After 10 years,

a+10=2(b+10)

a=2b+10 (2)

From 1 and 2,

3b−10=2b+10

b=20

And, a=2b+10=2×20+10=50 years

Thus, age of A = 50 years and age of B = 20 years

Answered by TGAush15
1

Step-by-step explanation:

Let the age of A be a, and age of B be b

Now, a−5=3(b−5)

a=3b−10 (1)

After 10 years,

a+10=2(b+10)

a=2b+10 (2)

From 1 and 2,

3b−10=2b+10

b=20

And, a=2b+10=2×20+10=50 years

Thus, age of A = 50 years and age of B = 20 years.

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