Question

Five years ago, A was thrice as old as B and ten years later, A shall be twice as old as B. What is the present age of A.​

Answer 1

Answer:

Let the present age of A be x and B be y.

Given that 5 years ago age of A was thrice the age of B.

That is, x - 5 = 3 (y - 5)

Also after ten years age of A is twice the age of B.

That is, x + 10 = 2 ( y + 10 )

By solving two equations we get,

- 15 = y - 35

y = -15 + 35 = 20

Substituting y = 20 in any of the equations we get,

x - 5 = 3 ( 20 - 5 )

x - 5 = 3 * 15

x - 5 = 45

x = 45 + 5 = 50

Therefore the present age of A is 50 years.

Answer 2

Answer:

50 years

Step-by-step explanation:

hope its correct thank you ♡(∩o∩)♡