Five years ago, A was thrice as old as B and ten years later A shall be twice as old as B. what are the present ages of A and B?
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Five years ago, A was thrice as old as B and ten years later, A shall be twice as old as B. What are the present ages of A and B? What is the sum?
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Francis Fasesin, Managing Director. (2012-present)
Answered Jul 12
Let x be the age of A and y the age of B 5 years ago.
Then 5 years ago,
x = 3y…..Equation 1.
10 years later, A will be (x + 10) years old while B will be (y+10) years old.
We know that 10 years later A is twice as old as B.
Therefore,
x+ 10 = 2(y+10)
From Equation 1, x=3y
Hence 3y+10= 2(y+10)
3y + 10 = 2y+20
3y-2y= 20–10
Hence y=10.
5 years ago A was 30 and B was 10
Present ages:
A= 35
B= 15.
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3 ANSWERS

Francis Fasesin, Managing Director. (2012-present)
Answered Jul 12
Let x be the age of A and y the age of B 5 years ago.
Then 5 years ago,
x = 3y…..Equation 1.
10 years later, A will be (x + 10) years old while B will be (y+10) years old.
We know that 10 years later A is twice as old as B.
Therefore,
x+ 10 = 2(y+10)
From Equation 1, x=3y
Hence 3y+10= 2(y+10)
3y + 10 = 2y+20
3y-2y= 20–10
Hence y=10.
5 years ago A was 30 and B was 10
Present ages:
A= 35
B= 15.
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