Question

five years ago a woman is a square of her son's age 10 years and her age will be twice that her son age find the age of the son 5 years ago and the present age of women​

Answer 1

Answer:

Step-by-step explanation:

Let Sons age = x

Let Womens age = y

y - 5 = (x - 5)² -------------1

y + 10 = 2(x+10)----------2

Equation 1

y - 5 =x² - 10 x + 25

y = x² - 10x + 30

Equation 2

y = 2x +10

Substituting The Value Of y in equation 1

2x + 10 = x² - 10x + 30

x² - 10x - 2x + 30 - 10 = 0

x² - 12x + 20 = 0

x² - 2x - 10x + 20 = 0

x(x - 2) -10(x - 2) = 0

(x - 10)(x - 2) = 0

x = 10 or x = 2[ x cant be 2 as five years ago it would be negative age]

therefore, sons present age = 10

1. So sons age five years ago = 5yrs

Substituting The Value Of x in equation 2

y = 2x + 10

y = 2 * 10 + 10

y = 20 + 10

y = 30 yrs

2. Women Present Age = 30 yrs