Math, asked by Shivanihani2145, 11 months ago

Five years ago , a woman's age was the square of her son's age . Ten years hence her age will be twice that of her son's age . Find: (i) the age of the son five year ago. (ii) the present age of the woman.

Answers

Answered by mayank539
0

Five years ago, a woman's age was the square of her son's age. Ten years hence her age will be twice that of her son's age. ... therefore, sons present age = 10 1


gyanibabacom: wrong
Similar questions