Question

five years ago a womens age was the square of her sons ago .ten years hence her age will be twice that her son's age .find the age of the son five year ago​

Answer 1

Answer:

y - 5 = (x - 5)² -------------1

y + 10 = 2(x+10)----------2

Equation 1

y - 5 =x² - 10 x + 25

y = x² - 10x + 30

Equation 2

y = 2x +10

Substituting The Value of y in equation 1

2x + 10 = x² - 10x + 30

x² - 10x - 2x + 30 - 10 = 0

x² - 12x + 20 = 0

x² - 2x - 10x + 20 = 0

x(x - 2) -10(x - 2) = 0

(x - 10)(x - 2) = 0

x = 10 or x = 2[ x cant be 2 as five years ago it would be negative age]

Therefore, sons present age = 10

So sons age five years ago = 5 yrs

Substituting The Value of x in equation 2

y = 2x + 10

y = 2 * 10 + 10

y = 20 + 10

y = 30 yrs

Therefore, Women Present Age = 30 yrs

Step-by-step explanation:

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