Question

Five years ago, Ajay was thrice as old as Sonu. Ten years later, Ajay will be twice as old as Sonu. How old are Ajay and Sonu? Solve it by graphical method.




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Answer 1

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Step-by-step explanation:

Five years ago,

Age of Ajay = x – 5 years

Age of Sonu = y – 5 years

Ajay was thrice as old as Sonu

X- 5 = 3(y – 5)

X – 5 = 35 – 15

X – 3y = -15 + 5

X – 3 y = - 10 ………..(1)

Ten years later,

Age of Ajay = x + 10

Age of Sonu = y + 10

Ajay will be twice as old as Sonu.

X+ 10 = 2(y+10)

X + 10 = 2y + 20

X – 2y = 10 ………..(2)

X – 3 y = - 10 ………..(1)

Subtracting equation (1) from equation (2) we get

Y= 20

x-3×20= -10

x= 60-10

X= 50

Hence age of Ajay = 50 years and age of Sonu= 20 years

Answer 2

Answer:

Five years ago,

Age of Ajay = x – 5 years

Age of Sonu = y – 5 years

Ajay was thrice as old as Sonu

X- 5 = 3(y – 5)

X – 5 = 35 – 15

X – 3y = -15 + 5

X – 3 y = - 10 ………..(1)

Ten years later,

Age of Ajay = x + 10

Age of Sonu = y + 10

Ajay will be twice as old as Sonu.

X+ 10 = 2(y+10)

X + 10 = 2y + 20

X – 2y = 10 ………..(2)

X – 3 y = - 10 ………..(1)

Subtracting equation (1) from equation (2) we get

Y= 20

x-3×20= -10

x= 60-10

X= 50

Hence age of Ajay = 50 years and age of Sonu= 20 year

Step-by-step explanation:

Snapid please?