Math, asked by Anonymous, 1 month ago

Five years ago, Ajay was thrice as old as Sonu. Ten years later, Ajay will be twice as old as Sonu. How old are Ajay and Sonu? Solve it by graphical method.


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Answers

Answered by Anonymous
10

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Step-by-step explanation:

Given :-

  • Five years ago, Ajay was thrice as old as Sonu.
  • Ten years later, Ajay will be twice as old as Sonu.

To Find :-

  • Both of them's ages

Solution :-

Let the present age of Ajay be = x              

And  the present age of Sonu be = y                

According to the Question,                

⇒ (x - 5) = 3(y - 5)                  

⇒ x - 3y = - 10 ... (i)                  

⇒ (x + 10y) = 2(y + 10)                  

⇒ x - 2y = 10 ... (ii)           

Subtracting equation (i) from equation (ii), we get

⇒ y = 20 ... (iii)                

Putting this value in equation (i), we get                

⇒ x - 60 = - 10                  

⇒ x = 50              

Hence, age of Ajay = 50 years and age of Sonu = 20 years.

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