Math, asked by Madhab11, 1 year ago

Five years ago ,Amit was three times as old as Armaan. Ten years later Amit would be twice as old as Armaan.How old are they?

Answers

Answered by adityakjha24
7
Let present age of Amit = x

present age of armaan = y

5 years ago ,

(x-5) = 3(y-5)

x-5 = 3y-15

x-3y = -10 ............(1)

10 yeras later,

(x+10) = 2( y +10)

x-2y = 10 ......... (2)


from solving equation (1) & (2)


x = 50 years

y = 20 years


so, present age of Amit = x = 50 years

present age of armaan = y = 20 years




Hope it helps
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Answered by pratik40
2

hi...
Let the Amit's age be x and age of Armaan be y.

Five years ago ,
Amit's age : x - 5
Armaan's age : y - 5

By the condition,
x - 5 = 3(y - 5)
x - 5 = 3y - 15
x - 3y = -15 + 5
x - 3y = -10 .........................(1)

10 years later ......

Amit's age : x + 10
Armaan's age : y + 10

By the 2nd condition ,

x + 10 = 2(y + 10)
x + 10 = 2y +20
x - 2y = 20 - 10
x - 2y = 10 .........................(2)

[Subtracting equation no. (2) from (1)]

x - 3y = -10
x - 2y = 10
_________
-y = -20

y = 20

Substitute y = 20 in equation no. (2)
x - 2y = 10
x - 2(20) = 10
x - 40 = 10
x = 10 + 40
x = 50

solution...
x = 50 \:  \:  \: . \:  \:  \: y = 20
Thus ,
The Amit is 50 yrs old and Armaan is age is 20yrs old.

hope \: this \: helps...


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