Math, asked by parsewar, 1 year ago

five years ago, Amit was three times as Old as armaan. ten years later Amit would be twice as old as armaan. how old are they now?

Answers

Answered by ShuchiRecites
8
Hello Mate!

Let the persent ages of Amit and Armaan be x and y respectively

5 years ago, there ages will be in equation :-

x - 5 = 3( y - 5 )
x- 5 = 3y - 15
x - 3y - 5 + 15 = 0
x - 3y + 10 = 0 ------(1)

x + 10 = 2( y + 10 )
x + 10 - 2y - 10 = 0
x - 2y = 0 -------(2)

(1) - (2)

x - 3y + 10 = 0
-( x - 2y ) = 0

- y + 10 = 0
y = 10

Keeping value of y in 2nd eqn

x - 2y = 0
x - 2 × 10 = 0
x = 20

Hope it helps☺!✌

ShuchiRecites: thanks frnd
Answered by Anonymous
7
Let the present age of Amit be x.
Let the present age of Armaan be y.

Given that 5 years ago, Amit was three times as old as Armaan.
x - 5 = 3(y-5)
x - 5 = 3y - 15
x = 3y - 10---------(i)

Given that ten years later, Amit would be twice as old as Armaan.
x + 10 = 2(y + 10)
x + 10 = 2y + 20
x = 2y + 10---------(ii)

On solving (i) and (ii), we get
3y = 2y + 20
3y - 2y = 20
y = 20----------(iii)

Substituting (iii) in (i), we get
x = 3y - 10
= 3(20) - 10
= 60 - 10
= 50.

Therefore, the present age of Amit is 50, &
the present age of Armaan is 20.

hope \: it \: helps \: you. \\ .dev.

ShuchiRecites: gr8 answer frnd
ShuchiRecites: :)
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