Question

Five years ago, Ankith was 3 times as old as Bhavana. If Bhavana is 20 years younger to Ankith, find their present ages.​

Answer 1

Answer:

In 5 years time I will be 3 times as old as I was 3 years ago. How old am I now?

I love time travel. Forward in time, 5 years. Backwards in time, 3 years.

Solving this is just a matter of writing it all down in the form of an equation.

Since we are jumping forwards and backwards in time I’m going to let ‘x’ equal my age NOW.

In 5 years time would be ‘x+5’.

The phrase ‘I will be’ becomes our ‘equals’ sign (=)

Then all we have left is the phrase ‘..3 times as old as I was 3 yrs ago..’

which i think would be 3(x-3)

So the equation becomes: x+5=3(x-3)

Solving for ‘x’:

—->3x-9=x+5

—->2x-9=5

—->2x=14

—-> x=7

So, 3 yrs ago I was 4 yrs old. In 5 yrs I will be 12 yrs old, which is 3x times older than I was 3 yrs ago (3x4=12) so ‘7’ is the correct solution.

Let the current age be x.

In 5 years time, that is,

5 years into future from current age, the age will be = x+5

3 years ago, that is,

3 years into past from current age, the age will be = x-3

Now lets equate,

In 5 years time = x+5

I will be 3 times = 3(something)

as I was 3 years ago = x-3

The equation becomes: (x+5) = 3(x-3)

=> x+5 = 3x-9

=> 2x = 14 (Moving x to the left and constant values to the right)

=> x = 7

Answer 2

Answer:

The present ages of Ankit and bhavana are 35 years and 15 years respectively.

Step-by-step explanation:

Let the present ages of ankit and bhavana be x and y years.

Given that,

5 years ago ankit was 3 times as old as bhavana.Therefore,we write

$x-5=3(y-5)= > x-3y+10=0-- > (1)$

Also given that,

Bhavana is 20 years younger to ankit.Hence we write

$y=x-20= > x-y-20=0-- > (2)$

Solving the equations 1 and 2,we get the values of ages as

$x=35,y=15$

Therefore,

The present ages of Ankit and bhavana are 35 years and 15 years respectively.

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