Five years ago,anu thrice as old as sonu after ten years ,Anu will be twice as old as sonu .how old are anu and sonu,please sent only correct answer.
Answers
Given :
- Five years ago,anu thrice as old as sonu.
- After ten years ,Anu will be twice as old as sonu .
To find :
- The age of Anu's and Sonu's =?
Step-by-step explanation :
Let, the present age of Anu =x year
Then, the present age of Sonu =y year
Five years ago Anu's age = x – 5years
Five years ago Sonu's age = y–5years
It is Given that,
Anu was thrice as old as Sonu,
As per question,
x − 5 = 3 (y – 5)
x – 5 = 35 – 15
x – 3y = −15 + 5
x – 3y = −10 ....(1)
Now,
After 10 years Anu's age will, x + 10 years
After 10 years Sonu's age will be = y + 10 years
It is Given that,
Anu will be twice as old as Sonu,
As per question,
x + 10 = 2( y + 10)
x + 10 = 2y + 20
x – 2y = 10 …..(2)
x – 3y = −10 …..(1)
Subtracting equation (1) from equation (2), we get,
x - 3y - (x - 2y) = 10 - (-10)
x - x - 3y + 2y = 10 + 10
y = 20
On putting the value of y = 20 in equation (1) we get
x − 3 × 20 = −10
x = 60 – 10
x = 50
Therefore, age of Anu =50 years and age of Sonu = 20 years respectively.
- Five years ago,anu thrice as old as sonu after ten years ,Anu will be twice as old as sonu.
- Present age of sonu and anu.
- Let the present age of Anu be x years.
- Let the present age of sonu be y years.
★ According to question:-
5 years ago,
Age of Anu = ( x - 5 ) years
Age of sonu = ( y - 5 ) years
Anu was thrice as old as sonu.
x - 5 = 3(y - 5)
x - 5 = 3y - 15
x - 3y = -15 + 5
x - 3y = -10 ---(1)
After ten years,
Age of Anu = x + 10
Age of sonu = x + 10
Anu will be twice as old as sonu.
x + 10 = 2(y + 10)
x + 10 = 2y + 20
x - 2y = 20 - 10
x - 2y = 10 ---(2)
★ Using elimination method:-
Substract eq(2) from eq(1) :-
Then we get,
0x - y = -20
Putting value of y in eq(1) :-
x - 3(20) = -10
x - 60 = -10
x = -10 + 60
Hence,
The present age of Anu = x = 20 years.
The present age of Sonu = y = 50 years.