Question

Five years ago, Anu was thrice as old as Sonu. After ten years, Anu will be twice as old as Sonu. How old are Anu and Sonu?
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Answer 1

Answer:-

Let the age of Anu be x years and Sonu be y years.

5 Years Ago,

Age of Anu = x - 5 years

Age of Sonu = y - 5 years

A.T.Q.

( x - 5) = 3(y-5)

= x = 3y - 15 + 5

= x = 3y - 10 _______________(1)

Ten Years Later,

Age of Anu = x + 10 years

Age of Sonu = y + 10 years

A.T.Q.

( x + 10) = 2(y + 10)

= 3y - 10 + 10 = 2y + 20

= 3y - 2y = 20

= y = 20

Substituting ( y = 20) in eq(1).

= x = 3y - 10

= x = 60 - 10

= x = 50

Hence,

Anu's age = x = 50 years

Sonu's age = y = 20 years.

Answer 2

Let the present age of Nuri =x year

And present age of Sonu =y year

Five years ago

Age of Nuri =x–5years

Age of Sony =y–5years

Nuri was thrice as old as Sonu

X−5=3(y–5)

X–5=35–15

X–3y=−15+5

X–3y=−10 ………..(1)

Ten years later,

Age of Nuri =x+10

Age of Sonu =y+10

Nuri will be twice as old as Sonu.

X+10=2(y+10)

X+10=2y+20

X–2y=10 ………..(2)

X–3y=−10 ………..(1)

Subtracting equation (1) from equation (2) we get

Y=20

Plug this value in equation first we get

X−3∗20=−10

X=60–10

X=50

Hence age of Nuri =50 years and age of Sonu =20 years

Step-by-step explanation:

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