Five years ago Bittu was twice as old as Tinku.Ten years later Bittu's age will be ten years more than Tinku's age.Find their present ages.What was the age of Bittu when Tinku was born.Solve it graphically.
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Given :-
- 5 years ago , Bittu = 2 * Tinku .
- 10 years later , Bittu = (Tinku + 10) years old.
To Find :-
- Their Present ages.
- The age of Bittu when Tinku was born .
Solution :-
Let us assume that, 5 years ago,
- Bittu was = 2x years old.
- Tinku was = x years old.
so,
→ Present age of Bittu = (2x + 5) years.
→ Present age od Tinku = (x + 5) years.
then,
→ 10 years later Bittu age = (2x + 5) + 10 = (2x + 15) years.
→ 10 years later Tinku age = (x + 5) + 10 = (x + 15) years.
A/q,
→ Bittu age - Tinku age = 10
→ (2x + 15) - (x + 15) = 10
→ 2x - x + 15 - 15 = 10
→ x = 10 years.
therefore,
- Present age of Bittu = (2x + 5) = (2*10 + 5) = 25 years.
- Present age of Tinku = (x + 5) = (10+5) = 15 years.
- Age of Bittu when Tinku was born = 25 - 15 = 10 years.
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