Question

Five years ago, Bittu was twice as old as Tinku. Ten years later Bittu's age will be ten years more than Tinku's age. Find their present ages. What was the age of Bittu when Tinku was born. Solve it graphically.


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Answer 1

Answer:

Let the present age of Nuri =x year

And present age of Sonu =y year

Five years ago

Age of Nuri =x–5years

Age of Sony =y–5years

Nuri was thrice as old as Sonu

X−5=3(y–5)

X–5=35–15

X–3y=−15+5

X–3y=−10 ………..(1)

Ten years later,

Age of Nuri =x+10

Age of Sonu =y+10

Nuri will be twice as old as Sonu.

X+10=2(y+10)

X+10=2y+20

X–2y=10 ………..(2)

X–3y=−10 ………..(1)

Subtracting equation (1) from equation (2) we get

Y=20

Plug this value in equation first we get

X−3∗20=−10

X=60–10

X=50

Hence age of Nuri =50 years and age of Sonu =20 years