Question

five years ago, father's age was 2times the sum of ages of his three children.after five years, father's age can be obtained by subtracting 8from the sum of ages of the three children.father present age is​

Answer 1

Solution :-

Let us suppose that Father's age be x years and sum of ages of his three son's be y years.

Given :

Case I, Five years ago, Father's age was two times the sum of ages of his three children.

=> x - 5 = 2(y - 15)

=> x - 5 = 2y - 30

=> x - 2y = - 25 _____(i)

Case II, After five years, Father's age can be obtained by subtracting 8 from the sum of ages of the three children.

=> x + 5 = y + 15 - 8

=> x - y = 2 ______(ii)

Subtract equation (ii) from equation (i) we get,

=> (x - 2y) - (x - y) = - 25 - 2

=> x - 2y - x + y = - 27

=> - y = - 27

=> y = 27

Putting the value of y in equation (i),

=> x - 2 × 27 = - 25

=> x = - 25 + 54 = 29

Hence,

Present age of father is 29 years.

Answer 2

Answer is in the above attachment