Question

Five years ago, father's age was 4 times his son's age. Now the sum of their ages is 45 years then find their present age.​

Answer 1

Answer:

Step-by-step explanation:let the age of son = x

let the father age = 4 + x

sum of their ages = x ( 4+× )

= 4x + x square

according to the problem sum of their ages = 45

4x + x square = 45

x square + 4x - 45 =0

x square -5x + 9x - 45 = 0

x ( x - 5) + 9(x - 5) = 0

(x + 9) or ( x- 5) =0

x+9=0

x = -9

x-5=0

x=5

x can't be negative

so x is 5

present age of sun is x is