Five years ago, father's age was 5 times that of his son and after 3 years he will be 3 times as old as his son. Find the present age of son ?
Answers
Answer:
A father is 5 times as old as his son, and he will be 3 times as old as his child in 5 years. What are their present ages?
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Let son's present age be x,
As per statement father is 5 times as old as his son, therefore father's age is 5x.
In five years their ages will be son x + 5 and father 5x + 5.
The father will be 3 times as old as his child in 5 years.
5x + 5 =3 (x + 5)
5x + 5 = 3x + 15
5x - 3x =15 -5
2x = 10
x = 10/2
x = 5
Son's age is 5 years.
Father's age is 5x. Means 5 × 5=25 years
Answer son's age 5 years and father's age 25 years
Given:-
- Five years ago, father's age was 5 times that of his son.
- After 3 years, Father will be 3 times as old as his son.
To Find:-
- What is the present age of son ?
Solution:-
Let the present age of father be 'x' and the present age of son be 'y'
✫ Five years ago, father's age was 5 times that of his son.
- Father's age = (x – 5) years
- Son's age = (y – 5) years
Now,
✫ After 3 years, Father will be 3 times as old as his son.
- Father's age = (x+3) years
- Son's age = (y +3) years
Put the value of 'x' in equation 2) from equation 1)
On putting the value of 'y' in equation 1), we get
✧ Father's age = x = 45 years
✧ Son's age = y = 13 years
Hence, the father's age is 45 years and Son's age is 13 years
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