five years ago jacob age was seven times that of his son . after 5 years the age of Jacob will be three times that of his son. represent algebraic expressions
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Answered by
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Hey!!!!
Let the present ages of Jacob and his son be x and y years respectively.
ATQ,
Case 1
5 years ago
( x - 5 ) = 7( y - 5 )
=> x - 5 = 7y - 35
=> x - 7y + 30 = 0
Case 2
5 years Hence (future)
( x + 5 ) = 3( y + 5 )
=> x + 5 = 3y + 15
=> x - 3y - 10 = 0
Hope this helps
Let the present ages of Jacob and his son be x and y years respectively.
ATQ,
Case 1
5 years ago
( x - 5 ) = 7( y - 5 )
=> x - 5 = 7y - 35
=> x - 7y + 30 = 0
Case 2
5 years Hence (future)
( x + 5 ) = 3( y + 5 )
=> x + 5 = 3y + 15
=> x - 3y - 10 = 0
Hope this helps
Answered by
1
Answer:
ur answer in the pic Hope it helps you
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