Five years ago,Jacob’s age was seven times than that of his son. After 5 years, the age of Jacob will be three times that of his son.Represent the situation Algebraically and Graphically. please can u put graph also its urgent
Answers
Given : Five years ago,Jacob’s age was seven times than that of his son. After 5 years, the age of Jacob will be three times that of his son
To find : Represent the situation Algebraically and Graphically.
Solution:
Jacob age = J Years
Son Age = S Years
Five years ago,Jacob’s age was seven times than that of his son.
=> (J - 5) = 7(S - 5)
=> J - 5 = 7S - 35
=> J - 7S = - 30
After 5 years, the age of Jacob will be three times that of his son
=> J + 5= 3(S + 5)
=> J + 5 = 3S + 15
=> J - 3S = 10
J - 7S = - 30
J - 3S = 10
on Solving S = 10 & J = 40
Graph attached
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