five years ago ,jocab s age was seven times that his son after five years the age of jocab will be three times that of his son represent this situation algebracally and graphically
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Answer :- x = 40 and y = 10
Explanation :-
Let Jocab age be x and his son age be y years respectively.
According to the first condition we get,
(x + 5) = 3(y + 5)
x - 3y = 10 --- (1)
According to second condition we get,
(x - 5) = 7(y - 5)
x - 7y = - 30 ---(2)
From equation 1 and 2 we get
x = 3y + 10 ---(3)
Therefore substituting x = 3y + 10 in equation (2) we get,
x - 7y = - 30
3y + 10 - 7y = - 30
- 4y = - 40
y = 40/4
y = 10
Substituting y = 10 in equation (3) we get
x = 3y + 10
x = 3(10) + 10
× = 30 + 10
x = 40
Therefore, Jocab age is 40 years and his son age is 10 years.
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