Question

five years ago lucky would be trice as old as lovely 10 yrs later lovely would be trice as old as lovely how old are they now

Answer 1

Answer:

So, Lucky is 50 and Lovely is 20 now.

Step-by-step explanation:

Let x be lucky's age and y be lovely's age presently.

Then, five years ago,

                x - 5 = 3 (y -5)

                x - 5 = 3y -15

                x = 3y - 10

And, ten years later,

               x + 10 = 2 ( y + 10)

               x + 10 = 2y + 20

               x  = 2y + 10

Since you see that x = 3y - 10 and x = 2y + 10, then,

             3y - 10 = 2y + 10

             3y = 2y + 20

              y = 20

Substitute this value into x = 2y + 10

             x = 2 (20) + 10

             x = 50

So, Lucky is 50 and Lovely is 20 now.

Answer 2

Given :

• Five years ago lucky would be trice as old as lovely

• Ten years later lovely would be trice as old as lovely.

To find :

• The present age of their =?

Step-by-step explanation :

Let the present age of lucky be x

And the present age of lovely be y

1st Case :

Five years ago Lucky's age = x - 5

Five years ago Lovely's age = y - 5

According to the 1st Case : :

➟ x - 5 = 3 ( y - 5)

➟ x - 5 = 3y - 15

➟ x - 3y + 10 = 0 ...... (i)

Case 2nd :

Ten years later Lucky's age = x + 10

Ten years later Lovely's age = y + 10

According to the 2nd Case : :

➟ (x + 10) = 3(y + 10)

➟ x + 10 = 3y + 30

➟ x - 3y - 20 = 0 .... (ii)

So,

➟ x - 3y + 10 = 0 [From (i)]

➟ x - 3y = -10

➟ x = - 10 + 3y ...... (iii)

Substituting the value of x in eq 2

➟ -10 + 3y - 3y - 20 = 0

➟ -10 + y - 20 = 0

➟ -10 + y = 20

➟ y = 10 + 20

➟ y = 30

Hence, We get the value of y = 30.

Therefore, the present age of Lovely is 30 years.

Now, putting the value of y = 30 in equation (iii),

➟ x = - 10 + 3y

➟ x = - 10 + 3 × 30

➟ x = - 10 + 90

➟ x = 80

Hence, We get the value of x = 80.

Therefore, the present age of lucky = 80 years.