Question

Five years ago man was seven times as hos son . Five years hence father will be three ti.es of s son.Find their present age

Answer 1

Let The Age Of The Man Be x.

Now Age Of Son Be y.

According To 1st Condition

x-5 = 7(y-5)

x-5 = 7y-35

x+30 = 7y

x = 7y-30

According To Second Condition

x+5 = 3(y+5)

x+5 = 3y+15

Now Substitute Value Of x as 7y-30

7y-30+5 = 3y+15

7y-25 = 3y+15

4y = 40

y = 10

Now Age Of Father = x = 7y-30 = 7*10-30 = 40

So Age Of Father = 40 And AGe Of Son = 10

4y = 40 ...
father age is 40years
and sons be 10years

Answer 2

Hope it helped .
Present age of Father is 40 years and present age of son is 10 years